When the switch is closed in the primary circuit,the instantaneous induced current in the secondary circuit is:

In the diagram shown,if a bar magnet is moved along the common axis of two single-turn coils $A$ and $B$ in the direction of the arrow,what happens to the induced current?

The magnetic flux linked with a coil at any instant $t$ is given by $\phi = 5t^3 - 100t + 300$. The $e.m.f.$ induced in the coil at $t = 2 \ s$ is $....... \ V$.

The magnetic flux through a coil perpendicular to its plane is varying according to the relation $\phi = (5t^3 + 4t^2 + 2t - 5) \; Wb$. If the resistance of the coil is $5 \; \Omega$,then the induced current through the coil at $t = 2 \; s$ will be $.... \; A$. (in $.6$)

$A$ coil has an area $0.06 \ m^2$ and it has $600$ turns. After placing the coil in a magnetic field of strength $5 \times 10^{-5} \ Wb/m^2$,it is rotated through $90^{\circ}$ in $0.2 \ s$. The magnitude of average e.m.f induced in the coil is

$A$ metal loop of area $10 \,cm^2$ is placed in a region such that its area vector points along $\hat{k}$. The region contains a uniform magnetic field of magnitude $1.73 \,T$ that points in the direction $\hat{i}+\hat{j}+\hat{k}$. When the magnetic field is switched off, the field decreases to zero at a steady rate in $10 \,s$, then the magnitude of emf induced in the loop is (in $\,mV$)